Homework Answers
a) Probability that a selected car was involved in an accident
= 0.05 + 0.02 + 0.03 + 0.04
= 0.14
Probability that a selected car was involved in an accident = 0.14
b) Probability that a selected car involved in an accident was from year 1999
= 0.03
Probability that a selected car involved in an accident was from year 1999 is 0.03
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59090 23. A study of automobile accidents produced the following data: Proportion of all Probability of...
For a certain health insurance policy, losses are uniformly distributed on the interval [0, 450]. The...
For a certain health insurance policy, losses are uniformly distributed on the interval [0, 450]. The policy has a deductible of d and the expected value of the unreimbursed portion of a loss is 56. Calculate a (A) 60 (B) 87 (C) 112 (D) 169 (E) 224 27. A study of automobile accidents produced the following data: Probability of Model Proportion of involvement car 2014 2013 2012 Other all vehicles in an accident 0.16 0.18 0.20 0.46 0.05 0.02 0.03...
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13. (11pt) Automobile manufacturers are very interested in improving the average gas mileage of their newer vehicles. One manufacturer knows that for their hybrid model car, the gas mileages are normally distributed with a mean of 32 mpg. The new model of this car is about to ship out, so the manufacturer randomly selects a sample of 7 new hybrid cars and determines that the mean gas mileage is 29.5 mpg with a standard deviation of 1.32 mpg. Is there...
Adult diabetes: A National Center for Health Statistics data brief states that in 2013 9% of...
Adult diabetes: A National Center for Health Statistics data brief states that in 2013 9% of US. adults aged 18 and over have diagnosed diabetes. Suppose that this year, we select a random sample of 100 adults. The conditions are not met for use of a normal model since the expected number of adults with diagnosed diabetes is only 9 (9% of 100). Therefore, we ran a simulation withp = 0.09. Suppose that the sample has 15 adults (or 15%)...
Lesson 6.2.4: Binomial Distribution and Sample Proportions A sample proportion, such as the one computed in...
Lesson 6.2.4: Binomial Distribution and Sample Proportions A sample proportion, such as the one computed in Question 4, is equal to a number of successes (x), divided by the sample size (n). The notation for a sample proportion is p, and it is computed by the formula p = Each value of x corresponds to a unique sample proportion ( p ), as computed by this formula. For example, x = 1 implies p = + - 0.10. These events,...
Probability and I A recent Gallup Poll asked a simple random sample o cigarettes in the...
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Answer critical analysis questions. ISSUES AND APPLICATIONS Private or Public Auto Insurance: What is Best for...
Answer critical analysis questions.
ISSUES AND APPLICATIONS Private or Public Auto Insurance: What is Best for Canada? Concepts Applied: Capitalist, Command, and Mixed Systems; Productive Efficiency, Allocative Efficiency; and Equity t the cost of he codents a How does t In response to public outrage over styrocketing car insurance premiums, the consumers' Association of a completed a comprehensive report on auto insurance rates in Canada September 2003 in presenting the report the association noted that government-owned or public auto insurance...
For a certain health insurance policy, losses are uniformly distributed on the interval [0, 450]. The policy has a deductible of d and the expected value of the unreimbursed portion of a loss is 56. Calculate a (A) 60 (B) 87 (C) 112 (D) 169 (E) 224 27. A study of automobile accidents produced the following data: Probability of Model Proportion of involvement car 2014 2013 2012 Other all vehicles in an accident 0.16 0.18 0.20 0.46 0.05 0.02 0.03...
13. (11pt) Automobile manufacturers are very interested in improving the average gas mileage of their newer vehicles. One manufacturer knows that for their hybrid model car, the gas mileages are normally distributed with a mean of 32 mpg. The new model of this car is about to ship out, so the manufacturer randomly selects a sample of 7 new hybrid cars and determines that the mean gas mileage is 29.5 mpg with a standard deviation of 1.32 mpg. Is there...
Adult diabetes: A National Center for Health Statistics data brief states that in 2013 9% of US. adults aged 18 and over have diagnosed diabetes. Suppose that this year, we select a random sample of 100 adults. The conditions are not met for use of a normal model since the expected number of adults with diagnosed diabetes is only 9 (9% of 100). Therefore, we ran a simulation withp = 0.09. Suppose that the sample has 15 adults (or 15%)...
Lesson 6.2.4: Binomial Distribution and Sample Proportions A sample proportion, such as the one computed in Question 4, is equal to a number of successes (x), divided by the sample size (n). The notation for a sample proportion is p, and it is computed by the formula p = Each value of x corresponds to a unique sample proportion ( p ), as computed by this formula. For example, x = 1 implies p = + - 0.10. These events,...
Probability and I A recent Gallup Poll asked a simple random sample o cigarettes in the past week?" Suppose that in fact 20 question. The proportion of the sample who answer this, we simulated 1000 samples of size n=1600 from a populatie smoked cigarettes in the past week. The results of this simula the percentage column and write your answers as decimals done for you as an example.) om sample of 1600 American adults, "Have you, yourself smoked any ose...
Answer critical analysis questions.
ISSUES AND APPLICATIONS Private or Public Auto Insurance: What is Best for Canada? Concepts Applied: Capitalist, Command, and Mixed Systems; Productive Efficiency, Allocative Efficiency; and Equity t the cost of he codents a How does t In response to public outrage over styrocketing car insurance premiums, the consumers' Association of a completed a comprehensive report on auto insurance rates in Canada September 2003 in presenting the report the association noted that government-owned or public auto insurance...
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