Question 7 How many grams of KAl(SO4)2 • 12 H2O (474.39 g/mol) can be produced from...

Question

Question

Question 7

How many grams of KAl(SO₄)₂ • 12 H₂O (474.39 g/mol) can be produced from 1.83 g of aluminum (27 g/mol)?

(report 2 digits after the decimal point)

__________ g KAl(SO₄)₂ • 12 H₂O (s)

Question 8:

If you recover 27.7 g of alum from question 7, what is the percent yield of this process?Question 8

(report as a %, not in decimal form; 2 digits before the decimal point)

__________ % yield

Answer 1

Answer #1

$(7) 2A1S)+ 2KOH (92) + 22H2010) + 4H28041981> 2KAI(S04 12420 . +34218) Мо\мая 08 Alum — 44-39 mo Molar mag of Aluminium = 27/$

Answer 2

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