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A simple noncompetitive inhibitor of acetylcholinesterase binds to the enzyme to affect Vmax only; it does...

A simple noncompetitive inhibitor of acetylcholinesterase binds to the enzyme to affect Vmax only; it does not affect KM.

Part A For an inhibition constant of KI=2.9×10?4M, what concentration of inhibitor is needed to give a 90% inhibition of the enzyme? Express your answer using two significant figures and include the appropriate units. [I] =

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Answer #1

Ans. # Given, Vmax is decreased but Km remains unaffected. It is the characteristic of a non-competitive inhibition. Therefore, the given inhibitor is a non-competitive inhibitor.

# On a 100 unit scale-

            Vmax = 100

            Vmax,app = Vmax – 90% of Vmax = 100 – 90 % of 100 = 10

Mixed Inhibition Given- 100 Vmax Vmax,app= 10 KT0.00029 M Vmax Vmax,app Ki. α -1 100 a- -10 10 [1]-KI, (α-1) [1]= Now, 0.00

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