thanks
1) 13N7
0p1
4He2
2)a) 235U92
b) Mass disappeared = 2(1.007276 + 1.008665 + 0.000549)u = 4.03298u
3) Difference in mass = 6(1.007276 + 1.008665 + 0.000549)u - 12u = 12.09894u - 12u = 0.09894u
So, Mass of the produced carbon atom is less.
4) 14N7 + 1n0 = 14C6 + 1p1
HELP PLEASE ITS ON ATOMIC MASS AND NUCLEAR PROCESSES thanks ˝ Astronomy homework - due Friday,...
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