Homework Answers
Answer:
940 AA = 1880 A
1055 Aa = 1055 A & 1055a
5aa = 10 a
Total alleles = 4000
Total alleles, A = 1880 + 1055 = 2935
Frequency of allele, A = 2935 / 4000 = 0.73
Total alleles, a = 10 + 1055 = 10655
Frequency of allele, a = 1065 / 4000 = 0.27
The expected genotype, AA frequency = 0.73 * 0.73 = 0.5329
Number of AA individuals = 0.5329 * 2000 = 1066
The expected genotype, Aa frequency = 2* 0.73 * 0.27 = 0.3942
Number of Aa individuals = 0.3942 * 2000 = 788
The expected genotype, aa frequency = 0.27 * 0.27 = 0.0729
Number of Aa individuals = 0.0729 * 2000 = 146
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