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The equation x² + 2x – 20 = 0 has two solutions A and B where A <B and A = D * Preview and B = O t Preview Give your answers

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Answer #1

x2 + 2x - 20 = 0

The solutions of a quadratic equation ax2 + bx + c = 0 is given by

x = (-b \pm sqrt(b2 - 4ac)) / 2a

In this case, a = 1, b = 2 , c = -20

Therefore, solutions of x are

x = (-b \pm sqrt(b2 - 4ac)) / 2a

= (-2 \pm sqrt((2)2 - 4(1)(-20))) / 2(1)

= (-2 \pm sqrt(84) / 2

= (-2 \pm 2sqrt(21) / 2

= -1 \pm sqrt(21)

= -1 + sqrt(21) , -1 - sqrt(21)

=> x = 3.583, -5.583

Therefore,

A = -5.583

B = 3.583  

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