Question

parta-

Use linear approximation, i.e. the tangent line, to approximate as follows:Let f(x) = x ⁶.

The equation of the tangent line to f(x) at x = 2 can be written in the form y = mx+b
where is:
and where is:
Using this, we find our approximation for 1.8⁶is
Box 1: Enter your answer as a number (like 5, -3, 2.2) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Box 2: Enter your answer as a number (like 5, -3, 2.2) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity

partb-

Use linear approximation, i.e. the tangent line, to approximate $\frac 1(0.203)$ as follows: Let $f(x) = \frac 1x$ and find the equation of the tangent line to at a "nice" point near . Then use this to approximate $\frac 1(0.203)$ .

Box 1: Enter your answer as a number (like 5, -3, 2.2) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity

Answer 1

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