Question

using thevenin’s theorem find the power disspated in 20 Ohm resistor

Ri R3 20Ω

Answer 1

Given circuit Using Thevenins theorem to find R_th across terminals A & B, short circuit the voltage source we get 20 ohm is parallel to 5 ohm and result is in series with 12 ohm whose result in parallel with 16 ohm and whole in series with 2 ohm = [((20 parallel to 5 + 12) parallel to 16] + 2 20 parallel to 5 = 20 times 5/20 + 5 = 4 = [(4 + 12) parallel to 16] + 2 = [16 parallel to 16] + 2 = 8 + 2 R_th = 10 ohm to find V_th open circuit A & B terminals By circuit reduction technique reducing the portion in brackets gives rise to as it is open circuited no current flows through 2 ohm resistor by applying KVL - 4 + 4I + 12I + 16I = 0 32I = 4 I = 1/16A so current passing through 16 ohm resistor is 1/16 A voltage drop across 16 ohm resistor is nothing but Thevenins voltage which is given by