The 10 ohm resistor in the figure (Figure 1) is dissipating 20 W of power. How...

Question

Question

The 10 ohm resistor in the figure (Figure 1) is di

Answer 1

Answer #1

power = i^ * R

20 = i^2 * 10

i^2 = 2

i = 1.4142 amp

so power dissipated in 5 ohm

i^2 *R = 2 *5 = 10 W

suppose total current = I

i = 20/35 * I

I = 35/20 * i = 35/20* 1.4142 = 2.4748 amp

so current in right brance = 2.4748 - 1.4142 = 1.0606 A

powwer in 20 ohm = 1.0606² *20 = 22.49 watt

Answer 2

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