Question

P.25.14. Determine the axial force in the flanges and web of the channel section shown in Fig. P.25.14 when it is subjected t


| 1.0 mm ----0.5 mm Flange layup (0/45/-45/90] 200 mm Web layup [45/-45] 11.0 mm 100 mm FIGURE P.25.14
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer Given data :- 41.04 mm -0.5mm 200mm 1.0mm. * 100mm P= 40 KN, Ees 140,000 N/mm2 Et = 10,000 Nimm² alt = 5000 N/mm². VetDate Now Ebiti Ezi = 144106 x 2 + 1x100 for 1=1 a (28+1) x 106 = 29 x 106 m. Ez = 40 X 103 Ebiti Ezi - 29x106 = 1.37931 x 103Here bracketed answer shows required answer

Note:- Pflang=19.3104, KN for single flange and for both flange it is twice of Pflange

Add a comment
Know the answer?
Add Answer to:
P.25.14. Determine the axial force in the flanges and web of the channel section shown in...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT