Question

Sm 100 mm Consider the flat bar with shoulder joints shown in Fig. A which is subjected to a tensile force P-58 kN. The bar is made of Aluminum 6061 having maximum tensile strength Omar = 290 MPa. NOTE: plots of stress concentration factors for different types of loading can be found on page 6 (a) Determine the radiusr [mm] for the fillets. (b) An identical flat bar shown in Fig. B replaces the tensile load with a bending moment M=744 N-m. Repeat part (a) for this loading. (B) ES M

Answer 1

• For axial loading the fillet radius is 7.5 mm where as for the bending loading the fillet radius is 17.5 mm. First the stress concentration factor (K) would be calculated and with the help of appendix graphs the radius of fillet would be obtained for different loading condition (i.g for axial and bending ) (r/d).
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  Given data :- tensile force ap=58 KN=52x103 N. max. tensile strengthe 290 MPaor Mmm? Determine the radius y for the fillets. Step- we know 'k stress concentration Factor. ke max. stress valute near discontinuity Novminal stress for minimum cls. K.- Emax 66 So, calculating noronominal stress. For minimum cross section R P dit 60 - d. 58X103 N 60- 50mm x 8mm. 145 Mirosm? or MPa.
  
  From equation k = 290 Ni mm2 145 Nimm2 Ika c 2. step -@ from (flat Stoess con centration Bar with shoulder joint). old- 100 SO = 2. = For 8 d = 0.1.5 (From APPENDIR) 8 50.15 x 5O. V = 7.5mm. fillet os7.5 mm (b) How, tensile load replaces with bendling moment M: +44 Nm. For this. (a). GATEX stress C60) = Nominal Mboy I cgiven). Mb = 744 Nm. ' y = 일 25 mom. 1 h it A11 X7
  
  I- t.63 bas d =50 12 12 b=8 I- 8 x (50) want . 12 H-moon - (744x103) x (25) 8x (sos xறம் mm 42 (**.CS009) EN/mmt 5o = 223.2 Nimme 6 max .'. Ka 2go 2 2232 Fa 1.3 From APPENDIX. (Etat Bending). old = 0.35 taken foons graph) r', 85 0.35 X SO 7 = 17.5 mm.