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JIRJOILUIL 1) Find the rotation matrix needed that will give the principal stresses for [12 15 01 0 = 15 -4 0 MPa. lo 0 -5] C

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or We know that the form of stress Tensor matrix in T12 o Mpa Lo 0 -5 ] After comparing Ex= 12 6y=-4 52=-5, Exy=15 exy = 15 MRadios (R) = (1/2) = 34 11 hence principal stren 6=4+17 = 21 Mp4 62=17-4 = 13 Mpa but in compressive in nature 62 = -13m pao

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