Question

Help with this please

Write an 8086 pasm program which will: Prompt the user to enter an base-16 (hexadecimal) number from the keyboard. Store the number in the bx register 2) With an appropriate label, print the number in bx as a 16-bit binary value value value value. is Y or 'y' repeat from step 1). 3) With a second appropriate label, print the number in bx as an 8-digit base-4 4) With a third appropriate label, print the number in bx as a 6-digit base-8 (octal) 5) With a fourth appropriate label, print the number in bx as a 4-digit hexadecimal 6) Ask the user if he/she wishes to enter another number (Y/N) and if the answer (Ctr)

Answer 1

1.)
; program to do octal input and output
org 100h
section .data
prompt1: db "Please enter a decimal number: $"
prompt2: db 0Dh,0Ah, "The number in octal is:    $"
prompt3: db 0Dh,0Ah, "The number in decimal is:    $"

section .text
mov ah,9           ; print prompt
mov dx,prompt1
int     21h
call    dec_in      ; read value into bx
mov ah,9            ; print output label
mov dx,prompt2
int     21h 
call    hexout
mov ah,9            ; print output label
mov dx,prompt3
int     21h
call    dec_out     ; display the value in bx as hex
exit:
; exit to DOS
mov ax,4C00h        ; Normal Exit
int 21h             ; bye!

; dec_in will read a base 10 value from the keyboard and place it into the bx    register
dec_in: 
; save registers
push    ax
push    dx

xor bx,bx       ; bx holds accumulated input
mov ah,1        ; read char fcn
int 21h         ; read it into al
while1: 
cmp al,0Dh      ; char = CR?
je  finis       ; if so, we are done
push    ax      ; save the character read
mov ax,10       ; set up for multiply
mul bx          ; dx:ax <- bx * 10
mov bx,ax       ; put 16-bit result back in bx (assume no overflow)
pop ax          ; restore the char read
and ax,000Fh    ; convert character '0'-'9' to value 0-9
add bx,ax       ; add value to accumulated input
mov ah,1        ; read char fcn
int 21h         ; read next char into al
jmp while1      ; loop until done
finis:  
; restore registers
pop dx
pop ax
ret

2.)

; hexout will display the binary value in the bx register as a base 16 value    
hexout:
; save registers we will be using
push    ax
push    cx
push    dx
mov ah,2        ; display char fcn
mov cx,4        ; loop counter init
for1:               ; top of for loop
rol bx,4        ; rotate so digit is in lowest 4 bits
mov dl,bl       ; get low half in dl
and dl,0Fh      ;  and mask out all but 4 bits
cmp dl,9        ; dl <= 9?
jnbe    AtoF    ; if not, then it's A-F
or  dl,30h      ; convert 0-9 to '0'-'9'
jmp endif1      ; get ready to display
AtoF:   add dl,55   ; convert 10-15 to 'A'-'F'
endif1: int 21h     ; display char
loop    for1    ; loop until done
; restore registers
pop dx
pop cx
pop ax
ret

; dec_out will display the binary value in the bx register as a base 10 value   
dec_out:
; save registers we will be using
push    ax
push    bx
push    cx
push    dx

xor cx,cx       ; cx counts digits, initially zero
rept:
mov ax,bx       ; set up to divide by by 10
xor dx,dx       ; must have a 32 bit (unsigned) dividend
mov bx,10       ; divisor will be in bx
div bx          ; quotient will be in ax, remainder in dx
push    dx      ; push remainder on stack
inc cx          ; we generated another digit, so count it
mov bx,ax       ; the quotient goes back in bx
cmp ax,0        ; clever way to test if quotient is zero
jne rept        ; if not, generate next digit

mov ah,2        ; display character function
for2:               ; loop cx times
pop dx          ; pop digit to print
or  dl,30h      ; convert the digit to print to ASCII code
int 21h         ; display the character
loop    for2    ; and keep going until all digits displayed

; restore registers
pop dx
pop cx
pop bx
pop ax
ret

i tried for 3rd and 4th program but i dint get correct answers that's why i din;t post the answers.