Question

using assembly 8086, Convert a binary string to decimal. Accept buffered user input in the form of a 16-bit binary string. Convert to signed integer and print to the screen. If the user enters less than 16 bits, or input illegal character return an error message and prompt for input again.

Sample Execution:

Enter a 16-bit binary number: 100111100101110
The decimal signed integer equivalent is -24996

Enter a binary number: 11001011100
Error! Please enter exactly 16-bits: 100111100101110

Enter a 16-bit binary number: 110//^ 01100
Error! Illegal Characters detected. Please Enter a 16-bit binary number: 100111100101110
The decimal signed integer equivalent is -24996

Answer 1

8086 program to convert a 16 bit decimal number to binary

.MODEL SMALL

.STACK 100H

.DATA

        d1 dw 16

    .CODE

        MAIN PROC FAR

            MOV AX,

    @DATA

        MOV DS,

    AX

;load the value stored;

in variable d1

    mov ax,

    d1

;convert the value to binary;

print the value

    CALL PRINT

;interrupt to exit

    MOV AH,

    4CH INT 21H

    MAIN ENDP

        PRINT PROC

;initilize count

    mov cx,

    0 mov dx, 0 label1:;

if

    ax is zero

        cmp ax,

        0 je print1

;initilize bx to 2 mov bx, 2

;devide it by 2

;to convert it to binary

    div bx

;push it in the stack

    push dx

;increment the count

    inc cx

;set dx to 0

    xor dx,

    dx

        jmp label1

            print1:

;check if count

;is greater than zero

    cmp cx,

    0 je exit

;pop the top of stack

    pop dx

;add 48 so that it

;represents the ASCII

;value of digits

    add dx,

    48

;interrupt to print a

;character

    mov ah,

    02h int 21h

;decrease the count

    dec cx

        jmp print1

            exit : ret

                       PRINT ENDP

                           END MAIN