Question

A machine fills 24-ounce (according to the label) boxes with cereal. The amount deposited into the box is normally distributed with a mean of 24.8 ounces. What does the standard deviation have to be in order for 96% of the boxes to contain 24 ounces or more?
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Answer #1

From z table output:

P(z > -1.75) = 0.96

As per the given problem:

P(X > 24) = 0.96

Hence,

24- 24.8

\sigma = 0.457 ounces

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