Question

Please answer correctly or don’t answer at all thank you

have signhicant gold holdings. But many of these countries also have massive debes The following dats show the total value of product for nine countries (WondPress and Trading Economics websites, February especialily those in Europe, Many countrie 24, 2012) Cick on the datafile loge to reference the data DATA Gold Country 17.7 Prance Germany Indonesia 132 692 62 .Select for the total value of a country's gold holdings( bitions) as the independent variable B. at

Answer 1

$\begin{tabular}{rrrrr} \hline X & Y & XY & XX & YY \\ \hline 63 & 17.7 & 1115.1 & 3969 & 313.29 \\ 146 & 81.7 & 11928.2 & 21316 & 6674.89 \\ 203 & 83.2 & 16889.6 & 41209 & 6922.24 \\ 33 & 69.2 & 2283.6 & 1089 & 4788.64 \\ 147 & 119 & 17493 & 21609 & 14161 \\ 36 & 63.7 & 2293.2 & 1296 & 4057.69 \\ 50 & 9.9 & 495 & 2500 & 98.01 \\ 62 & 55 & 3410 & 3844 & 3025 \\ 487 & 93.2 & 45388.4 & 237169 & 8686.24 \\ \hline \end{tabular} \\ \sum X =1227.0, \sum Y =592.6\\ \sum XY =101296.1, \sum XX =334001.0, \sum YY =48727.0$

a)

c)

$\\ \hat y = a + bx \\ a = \frac{\sum Y * \sum XX-\sum X*\sum XY}{n\sum X^2 -(\sum X)^2} \\ a = \frac{592.6*334001.0 - 1227.0*101296.1}{9*334001.0 - 1227.0*1227.0} \approx 49.0767 \\ b = \frac{n\sum XY -\sum X*\sum Y}{n\sum X^2 -(\sum X)^2} \\ b = \frac{9*101296.1 - 1227.0*592.6}{9*334001.0 - 1227.0*1227.0} \approx 0.123 \\ \hat y = 49.0767+0.123x$

d)

$\begin{tabular}{rrrrr} \hline X & Y & XY & XX & YY \\ \hline 63 & 17.7 & 1115.1 & 3969 & 313.29 \\ 146 & 81.7 & 11928.2 & 21316 & 6674.89 \\ 203 & 83.2 & 16889.6 & 41209 & 6922.24 \\ 33 & 69.2 & 2283.6 & 1089 & 4788.64 \\ 147 & 119 & 17493 & 21609 & 14161 \\ 36 & 63.7 & 2293.2 & 1296 & 4057.69 \\ 50 & 9.9 & 495 & 2500 & 98.01 \\ 62 & 55 & 3410 & 3844 & 3025 \\ \hline \end{tabular} \\ \sum X =740.0, \sum Y =499.4\\ \sum XY =55907.7, \sum XX =96832.0, \sum YY =40040.76$
$\\ \hat y = a + bx \\ a = \frac{\sum Y * \sum XX-\sum X*\sum XY}{n\sum X^2 -(\sum X)^2} \\ a = \frac{499.4*96832.0 - 740.0*55907.7}{8*96832.0 - 740.0*740.0} \approx 30.7686 \\ b = \frac{n\sum XY -\sum X*\sum Y}{n\sum X^2 -(\sum X)^2} \\ b = \frac{8*55907.7 - 740.0*499.4}{8*96832.0 - 740.0*740.0} \approx 0.3422 \\ \hat y = 30.7686+0.3422x$