Homework Answers
Apply conservation of momentum to the sphere and cube
m1u1 + m2 u2 = m1v1 + m2 v2
The final speed of the sphere after collisiion is
v2 = 2 m1/ m1 + m2 ) u1 + (m2- m1/ m1 + m2) u2
since u2 = 0
v2 = 2 m1/ m1 + m2 ) u1
=2 (0.5)/(0.5+4(0.5) * 20
=8 m/s
the final velocity of the cube
v1 = ( m1- m2/ m1 + m2) u1
= (0.5-4(0.5)/0.5+4(0.5) * 20
=-12 m/s
(a)
Impulse = change in momentum of the sphere
=m2( v2- u2)
= 4(0.5) (8 m/s - 0)
= 16 kg m/s
(b)
change in momentum of the sphere is
=m2( v2- u2)
= 4(0.5) (8 m/s - 0)
= 16 kg m/s
(c)
v2 = 2 m1/ m1 + m2 ) u1
=2 (0.5)/(0.5+4(0.5) * 20
=8 m/s
(d)
v1 = ( m1- m2/ m1 + m2) u1
= (0.5-4(0.5)/0.5+4(0.5) * 20
=-12 m/s
magnitude of velocity is 12 m/s
toward left side
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