Question

# q10 - create function meanMedianMax() to meet the conditions below
# - accept a list of numeric values
# - add a docstring
# --- Compute the mean (average), median, and maximum of the values in the
# --- list. The mean is the average. The max is the largest value.
# --- The median is the value at the halfway point. If there are an even
# --- number of values in the list, the median is the average of the
# --- two middle numbers.
# - Hint: Both median and maximum are much easier if you sort the list
#
# - return a tuple of the mean, median and max values
#
# - RESTRICTIONS: You are not allowed to use built in max() function
#
# - params: list (of numeric values)
# - return: tuple (of three numeric values)

Answer 1

def meanMedianMax(lst):
    '''
        Compute the mean (average), median, and maximum of the values in the
        list. The mean is the average. The max is the largest value.
        The median is the value at the halfway point. If there are an even
        number of values in the list, the median is the average of the
        two middle numbers.
    '''
    lst.sort()
    median = None
    if (len(lst) % 2 == 1):
        median = lst[len(lst) // 2]
    else:
        median = (lst[len(lst) // 2 - 1] + lst[len(lst) // 2]) / 2
    maxValue = lst[-1]
    avg = 0
    for x in lst:
        avg += x
    avg = avg / len(lst)
    return (avg, median, maxValue)