Question

A data set includes cholesterol levels for heart attack patients and for a group of control patients. It is recommended that people try to keep their cholesterol level below 200. The following Minitab output is for the control patients. Test of mu - 200.00 vs. mu <200.00 Variable N Mean StDev SE Mean T P control 60 195.20 22.4 2.89 -1.66 0.051 (a) What are the null and alternative hypotheses being tested? Write them in symbols. Hoid200, H : > 200 where is the mean cholesterol level for the population of people similar to those in the heart attack group, OH = 200, H.: u < 200 where is the mean cholesterol level for the population of people similar to those in the heart attack group. Hoiu = 200, H.: + 200 where is the mean cholesterol level for the population of people similar to those in the control group. OH = 200, H.: > 200 where is the mean cholesterol level for the population of people similar to those in the control group. Hoiu = 200, H H <200 where we is the mean cholesterol level for the population of people similar to those in the control group. (b) What is the mean cholesterol level for the sample of control patients? (c) How many patients were in the sample? (d) Use the formula for the standard error of the mean to show how to compute the value reported by Minitab. --Select- -Select- = -Select...! (c) What values does Minitab report for the test statistic and the p value? test statistic = (Round the answer to two decimal places.) D-value = (Round the answer to three decimal places.) Identify the numbers that were used to compute the t-statistic, and verify that the reported value is correct. (g) What conclusion would be made in this situation, using a 0.05 level of significance? ---Select-- the null hypothesis. There is ---Select--- evidence to conclude that the mean cholesterol level for the population of people like the control patients is less than 200.

Answer 1

Gaiven that, Mean 1gs 20 st Dev= 6 = 22-4 S.E of Mean =289 Null hypothesis.'- Ho e-200 VS Hal< 200 Wheac at is the mean calesteaal level foo the populatlon of people similaa to those in the contool graup Mean chaolestcro) lerel for the sample of con too) patients-=1gs 20 .:0 patients the Tnean n d) Stand aTd escs 224 SE ot Mean 2.89 Test statistics!- 195-20-200 22.41160 t-- t--1.66 P-value is o-o5) guates than odoos P-value is eviden ce Conclusi on'- e fail to sejett Ho Theat is to conclude +hat the mean cholesterol level fos the populatian of people tike the ontaol patients is less than 200