An unknown resistor is connected between the terminals of a 6.5 V battery. Energy is dissipated...
An unknown resistor is connected between the terminals of a 6.5 V battery. Energy is dissipated in the resistor at the rate of 0.480 W. The same resistor is then connected between the terminals of a 3.58 V battery. At what rate is energy now dissipated?
Homework Answers
Resistance
R=V2/P =6.52/0.48
R=88.02 ohms
Energy is dissipated at a rate when it is connected to V=3.58 Volts
P=V2/R=3.582/88.02
P=0.1456 Watts
Energy is dissipated in the
resistor at the rate=power loss across resistor=v*v/r
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