Question

Physics and Chemistry Department - Dr. Masoud PH2031-C Test#1 Name Spring-20 4/7/20 Q5) A- A glass bottle is filled with water up to a distance H from the top. The cylindrically shaped neck has an inner diameter of d-2 cm. H= 12 cm when the volume of water inside the bottle is 200-mL at 20°C. a) Calculate H if the bottle kept at 80°C (ignore the thermal expansion of the glass) b) Repeat part (a) if you take the thermal expansion of glass into the account Coefficient of Volume expansion of water is 210x10-6 °C Coefficient of Linear expansion of glass is 9x10-6 °C -di-2cm a) AV =0,02m H = 12cm =,12m @ T-20° Glass V-200ml bottle 20 the diameter of the rod is 8.

Answer 1

Coefficient of Volume expansion of water Yw=210x108/6 Initial temperature T = 20° , final Temperature=80°c Voluone of water = 200ml = 200 cm3 change in volume of water AV=YW VDT DV= 210x/ 0x200x60 = 2.52 cm3 here DV= Id²h, Here h increase in height go h = 4OV = 4x2.52 = 0.802 con T2² 3.14x4 So new value of TH=12 h = 11. 1978cm b) Coefficient of linear expansion of Glass dg=94166/ec Coefficient of volume expansion of glass=32g Yg= 2781660°c) Net coefficient of volume expansion 4 = Yw - Yg = (210-27 38/56 = 1838/5 7°C change in volume DV= YXD T = 1838/06 X 200 X 60 LOV=2.196 cm3 Here again DV=Idh = YDY = 4x 2.196 = 0.7cm Td2 3.1484 so new youe of H = 12 -0.7 = 103 cm TH=1103 cm