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homework # # FREE AS A AA EVEVEJ -PA EEEEE Är 2 Abedre Autobate AaBbci ABCD ABCDE Due: In Class of Feb 19th, 20204 You must
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Answer #1

1. a) (10110011)2 = ( 1*27 + 0*26 + 1*25 + 1*24 + 0*23 + 0*22 + 1*21 + 1*20 ) = ( 128 + 0 + 32 + 16+ 2+ 1) = (179)10

1. b) (1101101)2 = ( 1 * 26 + 1*25 + 0*24 + 1*23 + 1*22 + 0*21 + 1*20 ) = (64 + 32 + 0 + 8 + 4 + 1) = (109)10

2. a)

(94)10 ==> ( 94 % 2 ) = 0 ( 0 is Remainder for 92/2 )

(94 / 2) = 47 ==> ( 47 % 2 ) = 1

(47 / 2) = 23 ==> ( 23 % 2) = 1

(23 / 2) = 11 ==> ( 11 % 2) = 1

(11/ 2 ) = 5 ==> (5%2) = 1

(5/ 2 ) = 2 ==> (2 % 2 ) = 0

( 2/ 2) = 1 ( stop if x/2 is 0 or 1)

Writing the resultant remainders in buttom to up order : ( 1 0 1 1 1 1 0) 2 .

2. b)

( 134 )10 => (134 % 2) = 0

(134/ 2) = 67 ==> (67 % 2 ) = 1

(67 / 2 ) = 33 ==> ( 33 % 2) = 1

(33 / 2) = 16 ==> ( 16 % 2 ) = 0

(16/ 2) = 8 ==> ( 8 % 2) = 0

(8 / 2) = 4 ==> ( 4 % 2) = 0

( 4 / 2) = 2 ==> (2 % 2 ) = 0

( 2/ 2) = 1 ( stop if x/2 is 0 or 1)

Writing the resultant remainders in buttom to up order : ( 1 0 0 0 0 1 1 0) 2 .

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