Question

please take y = 4

5. For the circuit given in Figure 5, a) Calculate the equivalent load impedance seen by the voltage source (reflected from secondary to primary). b) Calculate the primary current and voltage of the transformer. c) Calculate the secondary current and voltage of the transformer. Here, Rư= The largest value of the last 3 digits of your school number. Lı = The smallest value of the last 3 digits of your school number. If the smallest value is equal to 0, use 1. For example, if your school number ends with 349, 9 is the largest value and 3 is the smallest value. (15 points) R 12 R1 = 512 -R, (12) N1 = 1000 turns V2 N2 = 200 turns f= 50 Hz = 24020° V + V N 3 4, (mH) LOAD ideal transformer Figure 5

Answer 1

Please like the answer if satisfied

Ri 12 R(e) 4(MH) 5:1 Given 240 Loov, f= 50 H} N = 1000 i na = 200 turns 52 Ri R . 42; 2= 2nH The secondary load referred to pri maly, 52 100.1 50ml 1 where ✓ R2 = (^/ / _ ) Rq 100 La = (59), a mi } RtRat jxza 3 - (105 + 15:7). 50 ml, I, 240 105+j15,7 2.261-8.5° 1x A) 1.32-8.50 C Scanned with CamScanner

the transformer And Applying kini poinary Vs = I, R, tv, V = 240 (0 - 5)(2.26 68.5° ✓ = (228.8-ju) v van ). v, = (45. 46 -30.34) v .., Required values are load impedance seen by a) Equivalent voltage source. } = (100 + ; 15.7) on b). Primary current. & voltage 1, - (2.23 -10,334) A v, = (228.8-j17) v c) secondary current & voltage. şq - (11.145-3167) A Veg - (45.76-3034) v. CS$canned with CamScanner
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