Question

1. Connect four diodes for proper use of full wave rectifier. Show Connection for 60Hz, 20Vrms AC input. 2. Determine waveshape of rectified output. Determine PIV on the diodes. 3. Find the peak to peak output ripple if filter capacitor C=200uf, and RL=50022 4. Determine Vpc. Can we use Vz=20v, Izk=5mA Zener regulator, explain? 5. Determine series resistor Rs for proper regulation if Pz=5W and show the Circuit 6. Determine, Ilmax 7. For variable RL at what value, maximum power would be dissipated in Zener? Pz? 8. For what value of RL minimum power would be dissipated in Zener? Pz=? 9. For RL=? 22, dissipated power in zener would be Pz=2W 10. Please draw the circuit and fill in your answers in the boxes Repeat this problem utilizing MultiSim, compare your calculations with simulation, consistent results would receive extra credit. (Different/inconsistent results would not get full credit) PIV=? Vrpp=? Voc=? Rs? Ilmax=? Ru=? PZmax=? Ru=? PZmin=? Ru=?2 Pz=2w VLE?

Answer 1

70, 037 GOHZ you to 2012 PIV = Vm (maxminput voltage) - 2055 = 28.28 V 27 764 Peak to peak outout sipple * 03 + C=200 Cute I 20V, elf RE5001 GoHz L yon 2 Vapps entre 2009 (50) CeBox (06) (NaP: 2357 V) ☺ Voce avesage value 16 output voltage with filtea capacitoa c= 2001F Vox = vm [2-utec - ava ( 2 Led] [Voc= 27:10] can we use Vz -20V, Tzk=5mA Zenea degulatoa 2. we can not use zenea diode as PIV is more thon the zenea breakdown voltage [PIV> Vz]