Question

The resistor R in the figure below dissipates 12 W of power. Determine the value of R. (Assume ΔV = 81 V.)

ΑΛ 5.0 Ω ξ40 Ω -Δ ξ30 Ω ER

R = Ω (larger value)
R = Ω

(smaller value)

0 0
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Answer #1

81-si - soil o 81- si - (to+R) iz = 0 ¿=¿, +62 30i, = 40 + R ) iz 81-sir-siz-soi, = 0 B1 - 351,- siz=0 81 - 351 to +R ) iz -590 4goor = 12 w 240 2500 + 1285² + 108500R 492075 R = 1225 R + 108500 R +240 2500 1225R² - 383575R + 240 25000 Ri=306-7280 R

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