Find the current in the 12-Ω resistor in the figure below. (Assume R1 = R3 = 5.0 Ω, R2 = R4 = 8.2 Ω, ΔV = 20 V.) (A)
Please answer the question correctly! Thank you so much in advance!
net resistance of upper wire
Ru = 5 + 8.2/2 = 9.1
net resistance of lower wire
RL = 2 + 4*12/ ( 4+12) = 5
net resistance of the circuit
R = 5 + 9.1 * 5 / ( 5+ 9.1) = 8.227
Current through circuit,
i = 20 / 8.227
i = 2.431 A
Current through lower wire
i' = 2.431* Ru / ( Ru + RL)
i' = 1.569 A
Current through 12 ohm
I = i' * 4/(4+12)
I = 0.392 A
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