Question

Experiment 1 - Marking 1. Section 2.2(a) Given x[n] = (0.7)"cos(0.25m) u[n] Mn] =-0.8y[n-l] + 0.2Mn-2] + 0.11n_3] + 1.2x[n] + 0.2x(n-1] [-1] = 0 I-21 0 f-3] = 1 Determine y[n] for n = 0, . . ., 9 via a MATLAB simulation of the LCCDE.

Using matlab

Answer 1

Hello,
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The following matlab code will plot y for the complete range and print the values of y from n=0 till 9

******** Matlab Code ********

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%%%%%% output simulations

n1 = 0:9;                                    % time vector
x1 = (0.7.^n1).*cos(0.25*pi*n1);             % signal x
n = [-3 -2 -1 n1];
x = [0 0 0 x1];                                 % signal x starting from time n=-3
y1 = zeros(1,length(x1));
y = [1 0 0 y1];

for count = 4:length(y)                         % start counter from y(0)
    y(count) = -0.8*y(count-1) + 0.2*y(count-2) + 0.1*y(count-3) + 1.2*x(count) + 0.2*x(count-1);
end

stem(n,y);
xlabel('n');
ylabel('y');
clc
y(4:end)

**** End of Code ******

Output:

1.5 0.5 -0.5 -1 -4 -2 2 4 6 10

vlues of y(0) till y(9) : 1.3000   -0.2460    0.5558   -0.6549    0.2739   -0.4851    0.3536   -0.2826    0.3291   -0.2387