Assume that men's heights have a distribution that is symmetrical and unimodal, with a mean of...
1. The distribution of heights of adult females: We assume that height is normally distributed with a population mean of 65 inches and a population standard deviation of 4 inches. 2. The distribution of heights of adult males: We assume that height is normally distributed with a population mean of 70 inches and a population standard deviation of 5 inches. a. Above what Z-score value does 2.5% of the normal distribution fall? Using the formula for Z-scores and the Z-score...
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 59.9 inches tall. (to 2 decimal places)Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of 1.8929
This Question: 5 pts A particular group of men have heights with a mean of 176 cm and a standard deviation of 6 cm Richard had a height of 196 cm. a. b. c. What is the positive difference between Richard's height and the mean? How many standard deviations is that [the difference found in part (a)? Convert Richard's height to a z score. d. f we consider "usual heights to be those that convert to z scores between -2...
People in a large city have heights that are normally distributed with a mean of 73.5 inches and a standard deviation of 3.98 inches. Suppose we obtain random samples of 60 people and find the mean height of people in the samples. One sample of 60 people has a mean height of 74 inches. What is the Z-score of this sample mean? Round the value to two decimal places.
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For a sample of 273 female heights, the mean was 64.9 inches and the standard deviation was 2.6 inches. The shortest person in this sample had a height of 58 inches. a. Find the z-score for the height of 58 inches. b. What does the negative sign for the z-score represent? c. Is this observation a potential outlier according to the three standard deviation distance criterion?Explain. a. Find the z-score z(Round to one decimal place...
Assume men's heights are normally distributed with mean 69.5 in. and standard deviation 2.4 in. If you randomly selected a man whats the probability that his height would be A. Over 6 feet B. Between 5'9 and 6'4 C. Less than 2 standard deviations above the mean D.What is height that separates the tallest 10% of men from the rest of men? What do we call this value? E. If 25 men were randomly selected what is the probability that...
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of 0.9 (to 2 decimal places) 71.52 Question 3. Points possible: 2 This is attempt 1 of 1. The mean amount of time it takes a kidney stone to pass is 15 days and the standard deviation is 4 days. Suppose that one individual is randomly chosen. Let X = time to pass the...
Suppose the heights of adult males in a population have a normal distribution with mean µ = 71 inches and standard deviation σ = 3 inches. Two unrelated men will be randomly sampled. Let X = height of the first man and Y = height of the second man. (a) Consider D = X − Y , the difference between the heights of the two men. What type of distribution will the variable D have? (b) What is the mean...
31 Details < > Question 2 Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of 2.9 (to 2 decimal places)
The mean height for a normal distribution of heights is 65 inches and the standard deviation is 3 inches. Let x represent height. a) P(62< x < 68) b) P(x >70) c) P(x<65)