Question

a) APPLICATION OF STATIC EQUATIONS OF STRUCTURAL ANALYSIS.

CALCULATE THE REACTIONS IN THE FRAME SUPPORTS [A] AND [D] SHOWN IN THE FOLLOWING FIGURE.

b) APPLY ONLY THE SEGMENT METHOD. DETERMINE THE VALUES OF THE SHORT FORCE [V] AND THE FLEXIBLE MOMENT [M] ALONG THE FRAME (NODES A, B, C AND D) AND PRESENT THE GRAPHICS WITH THE CORRESPONDING VALUES.

SEND SOLUTION PROCEDURE, VALUES IN GRAPHICS AND ANSWERS FRAMED IN BOXES.

NODE A: SIMPLE SUPPORT AND NODE D: ARTICULATED SUPPORT.

4k 4 K 2 k/ft 2 KFT B B с 3K -3 B C - [8 FT] [4 FT) [15 FT] [12 FT) RDXD A RAY RDy DIAGRAMA DE CUERPO LIBRE

Answer 1

E M8=0 E Fy=0 By - (2x9) + Cy=0 IMA Cy=0 MB +((2x8)x3 ]-mc Leyx12)=0 By - (2x8) + 19 =0 12 MB + 64-45-19x12=0 By = 173 k I (MB=0 12 Consider segment AB. 1 By = 173 12 В Bx * MB 15ft А Ray = 14 3k 12

Shear force diagram (SFD) and Bending moment diagram CBMD) By = 173 k & Axial force diagram (AFD) B B В B 173 12 BEO EK AMB=0 15ft AL SFD А BUD ГА 173 AFD 12k = 173 Ray 14K