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In the figure below, the block on the left incline

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Answer #1

The pulling force on the right incline must be equal to the pulling force in left incline to be in equillibrium.

Pulling force on the left = component of the force due to gravity along the inclined plane = mg*sin(theta_2)

Pulling force on the right= component of the force due to gravity along the inclined plane = 6.4*g*sin(theta_1)

so, mg*sin(theta_2) = 6.4*g*sin(theta_1)

m = 6.4*sin(60 deg)/sin(24 deg) = 13.63 kg.

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please help! In the figure below, the block on the left incline is 6.40 kg. theta_1...
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