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Question 3 1 pts What is the gravitational force of attraction between a mountain of mass 32 thousand tons and a person of ma

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Answer #1

QUESTION 3:

Use equation:

F = GMm/R2

F = (6.67 x 10-11 * 32000 x 103 kg * 74 kg) / (6 m)2

F = 5.929 x 10-5 N

F = 0.0593 mN

  • Answer = 0.0593 mN

------------------------------------------------------------------------

QUESTION 4:

Gravitational force between each masses:

F = G.M.M/R2

F = GM2/R2

Substitute given values:

F = 8.4417 x 1027 N

Net force on the third galaxy will be:

Fnet = sqrt (2F2 (1+cos 60)

Therefore, Fnet = 14.62 x 1027 N

  • Answer = 14.62 x 1027 N
  • Insert, A = 14.62

------------------------------------------------------------------------

QUESTION 5:

gh = g [ R ^ 2 / ( R + h ) ^2]

h = 9.3R

gh = g [ R ^ 2 / ( R + 9.3 R ) ^2]​​​​​​​

gh = g (1/106.09) = 0.0924 m/s2

  • Answer = 0.0924 m/s2
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