Question

Write the net ionic equation of the following reaction. Al(NO3)3(aq)+(NH4)3PO4(aq)->AlPO4(s)+3NH4NO3(aq)

Write the net ionic equation of the following reaction.

Al(NO3)3(aq)+(NH4)3PO4(aq)->AlPO4(s)+3NH4NO3(aq)

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Answer #1

Here each reactant and product is a salt so let's break them down into their corresponding anion and cation however since AlPO4 is in solid form, it remains as such because dissociation occurs only in aqueous solution.

Al(NO3)3 \rightarrow Al3+ + 3 NO3-

(NH4)3PO4 \rightarrow 3NH4+ + PO4 3-

NH4NO3 \rightarrow NH4+ + NO3-

Now lets write this for the above reaction

Al3+(aq) + 3 NO3-(aq) + 3NH4+(aq) + PO4 3-(aq) \rightarrow AlPO4 (S) + 3NH4+(aq) + 3NO3-(aq)

The common ion on both sides are cancelled by each other and we get

Al3+(aq) + PO4 3-(aq) \rightarrow AlPO4 (S)

Please provide a feedback for me.

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Write the net ionic equation of the following reaction. Al(NO3)3(aq)+(NH4)3PO4(aq)->AlPO4(s)+3NH4NO3(aq)
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