8. A proton enters perpendicular to a magnetic field at 4.50 x 10 m/s that causes...
A proton moves at 8.00×10^7 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 1 m. What is the field strength?
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an electric field through an electrical potential difference of 470 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 22 cm. 1.42e-3 How can you determine the speed at which the proton enters the region of constant magnetic field? What force provides the centripetal force that causes the proton...
A proton moves at 7.20 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.810 m. What is the field strength (in T)?
A proton enters a region of constant magnetic field, perpendicular to the fie and after being accelerated from rest by an electric field through an electric potential difference of - 350 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 21 cm. mt As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will...
A proton is launched with a speed of 4.50 x 106 m/s perpendicular to a uniform magnetic field of 0.360 T in the positive z direction. (a) What is the radius of the circular orbit of the proton? cm (b) What is the frequency of the circular movement of the proton in this field? Hz
Problem 3. a. An electron moving at 4.00x103 m/s in a 1.25-T magnetic field experiences a magnetic force of 1.40*10-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers. b. A proton moves at 7.50x107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.800 m. What is the field strength?
A high energy proton from the sun enters the Earths magnetic field at a speed of 6.0x10^6 m/s perpendicular to the field lines. The field is uniform and with strength B=4.5x10^-5 T. a) What is the magnetic force on the proton when it first enters the B-field? b) Calculate the radius of the protons path in the B field. c) determine the frequency and the period of the protons orbit.
2. A particle travelling at 1.80 x 104 m/s enters a perpendicular magnetic field, which has a strength of 7.50 x 10-3 T. The particle travels inside the magnetic field in a circular path with a radius of 5.00 x 10-2 m. The charge-to-mass ratio of this particle is A. 2.70 x 10°C/kg B. 2.40 x 106 C/kg c. 4.80 x 10' c/kg D. 1.76 x 10^1 C/kg
In a cloud chamber experiment, a proton enters a uniform 0.340 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.30 cm .
In a cloud chamber experiment, a proton enters a uniform 0.340T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.06cm . A. How fast was the proton moving? i got 2.04 x 10^6 m/s and it said Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures. i cant get it