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2. A particle travelling at 1.80 x 104 m/s enters a perpendicular magnetic field, which has a strength of 7.50 x 10-3 T. The
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È coutside) We know the magnetic force Fmag = q (JXB) Here, F may F こ = q (vx B) my² - c R * R = mv q m RB qB 1.8x104 Now, q

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