Question

1. f(m, n) w = w+1; n = 3; m = n * 10; main W = 0; int z[] = {10, 20, 30}; f(z[w], z[0]); print (z[w], z[0]); Given the code above, what is the output of the program if the values are passed by: a) Value. b) Value-result and address of z[w] is computed at the time of the call. c) Reference. d) Name. (Note: The order of evaluating the parameters of a subprogram are from left to right.)

Answer 1

a) In the above code, we can see that the function f is not returning any value (we can say that it is a void function), so the output of the following code will be the values written in the print statement that is z[w] and z[0], it has already assigned the value of w=0, so z[w] = z[0] that is 10 in the given array.

output:- 10 10

b) if the value-result and address of z[w] are computed at the time of the call, it will not show any effect on the output.

output:- 10 10

yes, you can print the address of the z[w], the address will be printed.

c) If we pass reference instead of value then the values of the variables will be changed

f(&m,&n) --> m=30 n=3

and it will update the value of z[0] and z[w] and it will not update the value of w because the reference of w is not passed the only reference of z[w] and z[0] is passed.

output:- 30 3

d) If we pass the name instead of value the values will be updated locally for that function only, and it will not update anything in the main function

so the output will be-

output:- 10 10

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