Question

4. A PV module is made up of 100 cells in series and 10 in parallel, with 1-sun isolation (1 kW/m²), each cell has short-circuit current Isc = 3 A at 27 °C, its reverse saturation current lo = 3*10-11 A, Parallel resistance Rp = 50 ohm, and series resistance R is 0.002 ohm, calculate a) Open circuit voltage and short circuit current of the PV module b) The load power when the current of the cell is 2.8 A. c) The total power loss the PV module when the cell current (I = 2.8 A), Hint: the loss occurs at the parallel and series resistors. > + Isc > Load

Answer 1

4. Given l0o cells n Senes OPen circuit votage Voc of the Pu moolul 100х Tе x Rр 'oc 3 x 50 100х 15 kv 1o cells in parale/ A1S Total short circuit cumrnt of 1hu PV mecule ox 3 - 30 A

load pouer uhen the carrent of cell is a SA PL - Ls R-28Rs)002.8x0 (3x50-2.8K0.002)M00 (2.8x 10 420 kw (c Total pouwer loss in the pv module Isc Rp t 2-8 Rs oss = 100 x Lo X (8x50 2-80 0z) o00 Loss 450 kw