Question

Write a C function named date() that receives an integer number of the long date, date form is yyyymmdd, such as 20070412; and the addresses of three variables named month, day, and year. determines the corresponding month, day, and year; and returns these three values to the calling function. For example, if date() is called using the statement

    longdate=20200411;

date(longdate, &month, &day, &year);

the number 4 should be returned in month, the number 11 in day, and the number 2020 in year.

In main() function, input a long date, store in variable longdate, call date()to get results, display the three values returned by the function.

For example, one running of the program is:

Enter a date in the form yyyymmdd:

20200411 <Enter>

The month is 4

The day is 11

The year is 2020

Hint1: function prototype of date() is : void date(int, int *, int *, int *);

Hint2: the value of expression “longdate%100”isday,

for example, the value of expression “20200411%100”is11. the value of expression“longdate/100 %100”ismonth, and so on.

Answer 1

Code

#include <stdio.h>

void date(int longdate, int *month, int *day, int *year){
*day = longdate%100;
longdate/=100;
*month = longdate%100;
longdate/=100;
*year = longdate;
}

int main() {
printf("Enter a date in the form yyyymmdd:\n");
int longdate , month , day , year;
scanf("%d" , &longdate);
   date(longdate, &month, &day, &year);
   printf("The month is %d\n" , month);
   printf("The day is %d\n" , day);
   printf("The year is %d\n" , year);
   return 0;
}

#include <stdio.h> o o o void date(int longdate, int *month, int *day, int year) { *day = longdate: 100; longdate/=100; *month = longdate: 100; longdate/=100; *year = longdate; o o on bu Poo o Fint main() { printf ("Enter a date in the form wwwyumdd: \n"); int longdate, month, day, year; scanf("%d", &longdate); date (longdate, Smonth, <day, year); printf ("The month is $d\n", month); printf("The day is $d\n", day); printf ("The year is d\n", year); return 0; oo o

OUTPUT