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Calculate the pH of a solution that is prepared by dissolving 0.470 mol of hydrocyanic acid...

Calculate the pH of a solution that is prepared by dissolving 0.470 mol of hydrocyanic acid (HCN, Ka = 6.17×10-10) and 0.180 mol of nitrous acid (HNO2, Ka = 4.60×10-4) in water and diluting to 2.30 L. Also, calculate the equilibrium concentrations of HCN, CN-, HNO2, and NO2-. Do not make an approximation unless the initial acid concentration is greater than 1000 × Ka. (Hint: The pH will be determined by the stronger acid of this pair.)

pH =

[HCN] =  M

[CN-] =  M

[HNO2] =  M

[NO2-] =  M

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