A solution is prepared by dissolving 0.075 mol of cyanoacetic acid (Ka-3.37×10-3) and 0.030 mol of...
please help me please i dont have questions remaining anymore A solution is prepared by dissolving 0.060 mol of iodoacetic acid (Kg = 6.68x10-4) and 0.040 mol of sodium iodoacetate in water to a total solution volume of 1.00 L. First, calculate a pH for the solution by assuming that the concentrations of ICH CO2H and ICH CO2 are equal to the formal concentrations of the substances dissolved. Submit Answer Tries 0/5 Next, calculate the pH for the solution based...
Calculate the pH of a solution prepared by dissolving 0.050 mol of benzoic acid (HA) and 0.50 mol of sodium benzoate (A-) in water sufficient to yield 1.00 L of solution. The Ka of benzoic acid is 6.30 x 10-5 A. 5.20 B. 1.30 C. 7.00 D. 3.20 E. 4.20
what is the ph of a solution prepared by dissolving 0.50 mol of acetic acid and 0.2 mol of sodium acetate in water and adjusting the volume of 0.5L if the pka for acetic acid is 4.75. of 0.010 mol of sodium hydroxide is added to the buffer solution from part (a), determine the ph of the new solution
QUESTION 14 Calculate the pH of a solution prepared by dissolving 0.270 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77X104 Enter your answer with three decimal places.
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid HCOOH and 0.230 mol of sodium formate HCOONa in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77x10. -4 Seleccione una: a. 10.463 b. 2.307 O O c. 2.099 d. 3.546 e. 3.952
A solution is prepared by dissolving 0.23 mol of formic acid and 0.27 mol of sodium formate in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the present in the buffer solution. The K, of formic acid is 1.8 x 10+ A formic acid B. sodium formate C water D. sodium E....
24. (25 points) A buffer solution was prepared by dissolving 0.500 mol formic acid and 0.060 mol sodium formate in enough water to make 1 L of solution, K, for formic acid is 1.80 x 104 a) Calculate the pH of the solution. b) If this solution was diluted to 10 times its volume, what would be the pH.
A solution is prepared by dissolving 0.045 mol of 4-nitrobenzoic acid (Ka = 3.61×10-4) and 0.030 mol of sodium 4-nitrobenzoate in water to a total solution volume of 1.00 L.First, calculate a pH for the solution by assuming that the concentrations of 4−(NO2)C6H4CO2H and 4−(NO2)C6H4CO2− are equal to the formal concentrations of the substances dissolved. Next, calculate the pH for the solution based on the equilibrium concentrations of 4−(NO2)C6H4CO2H and 4−(NO2)C6H4CO2−. Use the Henderson-Hasselbalch approximation to calculate the pH of...
Calculate the pH of a buffer solution prepared by dissolving 19.50 g of sodium cyanate NaCNO (65.01g/mol) in 1.00 M cyanic acid (HCNO) to a final volume of 1.00 liter of solution. Ka(HCNO) = 3.50 x 10-4
Calculate the pH of a solution that is prepared by dissolving 0.740 mol of hypochlorous acid (HCIO, Ka = 3.00x10-8) and 0.254 mol of hydrofluoric acid (HF, K, = 6.60*10-4) in water and diluting to 4.50 L. Also, calculate the equilibrium concentrations of HCIO, CIO-, HF, and F. Do not make an approximation unless the initial acid concentration is greater than 1000 ~ Kg. (Hint: The pH will be determined by the stronger acid of this pair.) pH = [HCIO]...