Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid HCOOH and...
QUESTION 14 Calculate the pH of a solution prepared by dissolving 0.270 mol of formic acid (HCO2H) and 0.230 mol of sodium formate (NaCO2H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77X104 Enter your answer with three decimal places.
A solution is prepared by dissolving 0.23 mol of formic acid and 0.27 mol of sodium formate in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the present in the buffer solution. The K, of formic acid is 1.8 x 10+ A formic acid B. sodium formate C water D. sodium E....
Calculate the pH of a solution prepared by dissolving 0.050 mol of benzoic acid (HA) and 0.50 mol of sodium benzoate (A-) in water sufficient to yield 1.00 L of solution. The Ka of benzoic acid is 6.30 x 10-5 A. 5.20 B. 1.30 C. 7.00 D. 3.20 E. 4.20
23. A 1.0 L buffer solution is prepared with 0.25 M formic acid (HCOOH) and 0.50 M sodium formate (HCOONa). HCOOH(aq) + H2O(aq) – HCOO (aq) + H30+(aq) pKa = 3.74 What is the pH of this buffer solution? (A) 3.74 (B) 4.04 (C) 4.50 (D) 4.20
24. (25 points) A buffer solution was prepared by dissolving 0.500 mol formic acid and 0.060 mol sodium formate in enough water to make 1 L of solution, K, for formic acid is 1.80 x 104 a) Calculate the pH of the solution. b) If this solution was diluted to 10 times its volume, what would be the pH.
3. Calculate the pH of a solution that contains 0.250 M HCOOH (formic acid) and 0.100 M NaCOOH (sodium formate). Given Ka = 1.8 x 10 - 4 for HCOOH. Please include the ICE table.
Answer Part B please 1.000 mol of formic acid (HCOOH) and 0.500 mol of sodium formate (NaCOOH) are added to water and diluted to 1.00 L. Calculate the pH of the solution. Ka 1.77 x 10-4 (4 marks) Enough HCl is added to the above solution (with negligible volume change) to bring the [H3O] up to 0.100 M. Find the pH of the resulting solution. (5 marks)
Calculate the pH of a solution prepared by dissolving 0.876 moles of carbonic acid (H2CO3) and 0.543 moles of sodium hydrogen carbonate (NaHCO3) in water sufficient to yield 1.00 L of solution. The Ka of carbonic acid is 4.5x10^-7. Explain answer please
Calculate the pH of a solution that is made up of 2.39 M formic acid (HCOOH) and 0.77 M sodium formate (NaOOCH)
A solution buffered at pH 3.90 is needed for a reaction. Would formic acid (HCOOH = HA) and its salt, sodium formate, NaHCO2 = NaA), make a good choice for this buffer? If so, what ratio of moles of A- and HA is needed? Use the Henderson Hasselbalch Equation. Ka formic acid = 1.8 x 10-4