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Use the References to access important values if needed for this question. Calculate the pH of a solution that is prepared by

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2a For a quadratic equation as²+bx+C =0 x = - b ± √b²_4ac =ON O2 + 6.6x104x - 0.466x104 = 0. ox. 1043c2 +66 -0.466 =0; a=104;

2 = V1-2525 x15O - 1.119 x10.5 = 1.12x10-5 Henleam = 0.203-4 = 0.203 - 0.0000112 = 0.20298 CN) n = = = |-12 x105 PH = 2.19 E

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