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Three identical lamps are connected in parallel and powered by a 6-Volt battery. Each lamp has 3 ohms of resistance. How much
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Answer #1

\\ R_1=R_2=R_3=3\ \Omega

\\ The\ equivalent\ resistance\ of\ parallel\ combination:\\ \\ \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

\\ \frac{1}{R}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1

\\ R=1\ \Omega

\\ V=6\ Volt

\\ Ohm's\ Law:\\ \\ V=IR

\\ The\ toat\ current\ delivered\ by\ the \ battery\ (I)=\frac{V}{R}

\\ I=\frac{6\ volt}{1\ \Omega}=6\ Ampere\ \ Ans.

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