Question

Question 2 Two non-identical amplifiers are required to run the traffic of a satellite at full load. Assume that amplifier 1 and amplifier 2 have constant failure rates of 2 = 0.0001 failure/hour and l = 0.0002 failure/hour respectively. Calculate this series system mean time to failure and reliability for a 100 hour mission assuming both amplifiers start operating at t=0. (Use back side of the paper to solve Page 2 of 5

Answer 1

Given that, Amplifier 1 Amplifies a Joulune rate failuu rate x = 0.0001 failureth = 0.0002 failure Ihr. The two non identical amplifiers are required to run Then the Load. 11 trafic of a satellite at full road. it should connect in cascaded format (se nies). Amp 2 Amp 2 (R) (R2) R, Reliability of Amplifies 1 R2 → Reliability of Amplifier 2. If the components have constant failure. Iracter, then the failure times of components are exponentially distributed we can say that Rilt) = edit - R, CA) = enit - R2 (A) = e-tat. total sieliability h For a series Connected system, the of secues system is given by Rs (t) = 7 Ri(t) tese no no. of components = 2 Rs (H) = I R; (4) i

di Rs (t) = R, (4), R2 (4) selit edzt -(1,6X2)t ce .: R56) -(0.0001 +0.0002](100) to find reliability t=100 as in abe question, it is asked to find for a 100 hr mission. Rs CtJ: 0.97045 The mean time to failure (MTTF) is MATE= 8 e 2 rest at MTTF - é - (x +*25€ et lê (X1XX2) ETO 1-(1, 4*2) - ( 18 ) [central t Aithe sot witte e MTTF: t2 0.0001 +0.0002 MTTF 3,333.33... hrs