Here
Power = 1/fe = 80.000
Therefore'
fe = 0.0125 m
Therefore
fo + fe = 1.6125
Therefore
fo = 1.6125 - 0.0125
= 1.6 m
Magnification = fo/fe
= 1.6/0.0125
= 128
(B)
Magnification is given as.
m= fo/fe
fo =m*fe
Here
fe +fo = d
So,
fe = d/(1+m)
Given m = 15
d = 42 cm
fe = 2.625 cm = 0.02624 m
Calculate the power of each lens.
Pe = 1/fe = 38.1 D
fo = 15 * 0.02624 = 0.3936 m
Po = 1/fo = 2.54 D
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