1. a. For a converging LENS with a focal length of 3.50cm, find the distance that...
1. a. For a converging LENS with a focal length of 3.50cm, find the distance that will result in an inverted image with an image distance of 5.00cm
b. is the image real or virtual
c. what is its magnification
please write legibly, thank you!
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1. a. For a converging LENS with a focal length of 3.50cm, find
the distance that...
An object's distance from a converging lens is 5.00 times the focal length (a) Determine the...
An object's distance from a converging lens is 5.00 times the focal length (a) Determine the location of the image. Express the answer as a fraction of the focal length. (b) Find the magnification of the image and indicate whether it is (c) upright or inverted and (d) real or virtual.
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
a) Suppose an object is placed 7.50cm from a converging lens with a 5cm focal length....
a) Suppose an object is placed 7.50cm from a converging lens with a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image: (upright or inverted, real or virtual, bigger or smaller). b) Use the lens equations to calculate the location of the image and its magnification. Describe the image: (upright or inverted, real or virtual, bigger or smaller).
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
(a) Find the object distance (in terms of f) for a thin converging lens of focal...
(a) Find the object distance (in terms of f) for a thin converging lens of focal length f if the image is real and the image distance is seven times the focal length. (Use any variable or symbol stated above as necessary. Enter your coefficient to two decimal places.) p = (b) Find the object distance (in terms of f) for a thin converging lens of focal length f if the image is virtual and the absolute value of the...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
An object is a distance of 6 64f from a converging lens, where is the lens's...
An object is a distance of 6 64f from a converging lens, where is the lens's focal length. (Include the sign of the value in your answers) (a) What is the location of the image formed by the lens? d_i = f (b) Is the image real or virtual real virtual (c) What is the magnification of the image? (d) Is the image upright or inverted? upright inverted
A converging lens has a focal length of 10.0cm. Construct accurate ray diagrams for object distances...
A converging lens has a focal length of 10.0cm. Construct accurate ray diagrams for object distances of (i) 20.0cm and (ii) 5.00cm. (a) From your ray diagrams, determine the location of each image. (b) Is the image real or virtual? (c) Is the image upright or inverted? (d) What is the magnification of the image? (e) Compare your resstuls with the value found algebraically. (f) Comment on difficulties in constructing the graph that could lead to difference between the graphical...
A converging lens has a focal length of 46.0 cm. If an object is at a...
A converging lens has a focal length of 46.0 cm. If an object is at a distance of 13.1 cm from the lens, determine the location d of the image, the magnification m, and the type of image, if it exists. d = -18.4 cm, m = 1.4, virtual and upright d = +18.4 cm, m = -1.4, real and inverted image does not exist d = 56.2 cm, m = -0.222, real and inverted d = -23.0 cm, m...
An object's distance from a converging lens is 5.00 times the focal length (a) Determine the location of the image. Express the answer as a fraction of the focal length. (b) Find the magnification of the image and indicate whether it is (c) upright or inverted and (d) real or virtual.
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
An object is a distance of 6 64f from a converging lens, where is the lens's focal length. (Include the sign of the value in your answers) (a) What is the location of the image formed by the lens? d_i = f (b) Is the image real or virtual real virtual (c) What is the magnification of the image? (d) Is the image upright or inverted? upright inverted
A converging lens has a focal length of 10.0cm. Construct accurate ray diagrams for object distances of (i) 20.0cm and (ii) 5.00cm. (a) From your ray diagrams, determine the location of each image. (b) Is the image real or virtual? (c) Is the image upright or inverted? (d) What is the magnification of the image? (e) Compare your resstuls with the value found algebraically. (f) Comment on difficulties in constructing the graph that could lead to difference between the graphical...
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