Question

An object with a density of 941.0 kg/m³ and a mass of 895.0 kg is thrown into the ocean. Find the volume that sticks out of the water. (use ?_seawater = 1024 kg/m³)

Answer 1

Mass of object m = 895 kg

density of object d = 941 kg/m³

density d = Mass / Volume = m/V

dencity of seawater d_w = 1024 kg/m³

Thus, volume of object:

V = m/d = 895/941 = 0.951 m³

Now according to Archimedes principle, when an object is thrown in water, it displaces the amount of water equal to its mass:

Thus the amount or volume of water having mass same as that of object:

V_w = m/d_w = 895 / 1024 = 0.874 m³

This is the amount of water displaced by the object and volume taken up by it when it is thrown in water.

Now only 0.874 m³ of its volume is in water.

Thus volume sticking out is:

V' = V - V_w= 0.951 - 0.874 = 0.77 m³