A 45 dB sound wave strikes an eardrum whose area is 4.1
a) sound intesity level, beta =
10*log*(I/Io)
here, Io = 10^-12 W/m^2
45 = 10*log(I/10^-12)
4.5 = log(I/10^-12)
==> I = 10^4.5 * 10^-12
= 3.16*10^-8 W/m^2
Power = Intenisty*area
= 3.16*10^-8*4.1*10^-5
= 1.297*10^-12 W
b) Energy = power*time
time = energy/power
= 1/1.297*10^-12
= 7.71*10^11 s
= 7.71*10^11/(365*24*60*60)
= 24448.2 years
A 48 dB sound wave strikes an eardrum whose area is 4.9 10-5 m2
Given:
Area=4.9 x 10^-5 m2
48db=
Intensity
in db
Convert intensity in decibels to intensity in
watts/m2:
48db=10 log (I / 1 x 10^-12)
divide both sides by 10.
48db/10=10 log ( I/ 1x 10^-12)/10
4.8db=log (I/1 x 10^-12)
use the law on logarithms.(b^y=x)
In this case, 4.8 is our y, 10 is our base and (I/ 1x 10^-12) is
our x.
(Remember that every logarithmic equation, if it has no specific
base, has a base of 10.)
10^4.8=I / 1 x10^-12
(eliminate the log expression)
6.30957344 x 10^4=I / 1 x 10^-12
cross multiplying we get,
6.30957344 x 10^-8 watts/m2= Intensity in
watts/m2.
we round off this value to 6.31 x 10^-8 watts/m2.
we use this intensity for calculating power.
I=P/A
6.31X10^-8watts/m2= P/ 4.9 x 10^-5 m2
cross multiplying, we get:
3.09 x 10^-12 watts.
calculating for the energy,
t= 1s
Break down watts into J/s
3.09 x 10^-12 J/s= E / 1S
3.09x10^-12 J = energy absorbed per second.
Solving for time,
P= E / T
3.09 x 10^-12 J/s = 1.0 J/ T
cross multiplying, we get:
3.09 x 10^-12 J (T)=(1.0J)(s)
then divide 3.09 x 10^-12 J by itself to isolate the unknown. Do
the same thing on the other side of the Eq.
T= 1.0J(s)/(3.09 x 10^-12J)
You get:
T= 3.24 x 10^11 s
I hope it helped you!!!
a> 45 = 10 log ( I/10^-12)
=> I = 3.16*10^-8
energy =3.16*10^-8 * 4.1*10^-5=1.29*10^-12
b> time =1/1.29*10^-12 =7.7*10^11 sec
Db = 10 log (I/I0)
at 45db
4.5 = log I/I0
I/I0 = 10^4.5
I = 10^4.5 *10^-12
I = 3.16*10^-8
Power = I*area
P = 1.296 *10^-12 J/s
this energy in 1sec,
1.296 *10^-12 J in 1 sec
so 1J will be in 7.71 *10^11 sec
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