Ans 4.8 :
We will use the ideal gas law , pV = nRT
T = 25 degrees C = 298.15 K
p = 0.80 atm
n = 1.5 moles
Putting all the values in law , we get :
0.80 x V = 1.5 x 0.08206 x 298.15
V = 45.9 L
So the volume occupied will be 45.9 L
Ans 4.9 :
Using the ideal gas law , pV = nRT , we get the relation : p1V1 T2 = p2V2 T1
p1 = 0.75 atm
V1 = 150 mL = 0.150 L
T1 = 10 degrees C = 283.15 K
p2 = ?
V2 = 500 mL = 0.500 L
T2 = 522 degrees C = 795.15 K
So putting all the values we get :
0.75 x 0.150 x 795.15 = p2 x 0.500 x 283.15
p2 = 0.632 atm
So the pressure exerted by the gas will be 0.632 atm.
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