Question

Write a program to subtract large unsigned integers. Your program should prompt and read in two large unsigned integers. The two large integers should be stored arrays, one array for each integer. The integers should be stored with one digit per location in the two arrays. The first integer should be no smaller than the second. Your program should subtract the second integer from the first. The result should be stored in an array, again one digit per location in the array. Your program should
then output the difference, there should be no leading zeros. Your program should be able to handle integers with up to 80 digits each. You should not use any concepts from java. In particular please do not use any classes (or struct) or any class methods. The one exception is that you may use cin, cout and the iostream class method.cin.get().
Test data:
123456789 and 123459999

IN C++ PROGRAMMING LANGUAGE PLEASE. THE ANSWER SHOULD NOT HAVE ANY LEADING ZEROES. for eg. 000003210. The answer should come as 3210 only. No extra zeroes on the front !!!

Answer 1

#include <iostream>
using namespace std;

int main()
{
unsigned long int num1,num2;
int arr1[80],arr2[80],arr3[80],r,len1,len2,i=0,j;
//Enter the first integer
cout << "Enter first integer: ";
cin >> num1;
//Enter the second integer
cout << "Enter second integer: ";
cin >> num2;
//loop to get the each digit from first number
while(num1 != 0)
{
// % - reminder of num1 / 10
r = num1%10;
//store the each digit in arr1
arr1[i] = r;
num1 = num1 / 10;
i++;
}
//store the length of arr1
len1 = i;
i=0;
//loop to get the each digit from second number
while(num2 != 0)
{
// % - reminder of num2 / 10
r = num2%10;
//store the each digit in arr2
arr2[i] = r;
num2 = num2 / 10;
i++;
}
//store the length of arr2
len2 = i;
r=0;
cout<< "Output: ";
//Displays the difference between second and first integer
for(i=len2-1,j=0;i>=0;i--,j++)
{
//Subtract the second and first integer
arr3[j] = arr2[i] - arr1[i];
//This logic is used to remove the leading zeros
if(arr3[j] > 0)
{
r = 1;
}
if(r>0)
{
//Print the each digit
cout << arr3[j];
}
}
return 0;
}

main.cpp #include <iostream> 2 using namespace std; 4 int main() unsigned long int num1, num2; int arr1[80], arr2[80], arr3[80],r, len1, len2,i=0,j; //Enter the first integer cout << "Enter first integer: "; cin >> num1; //Enter the second integer cout << "Enter second integer: "; cin >> num2; // Loop to get the each digit from first number while(num1 != 0) // % - reminder of num1 / 10 r = num1%10; //store the each digit in arr1 arr1[i] = r; num1 = num1 / 10; i++; //store the length of arri len1 = i; i=0; // Loop to get the each digit from second number while(num2 != 0) // % - reminder of num2 / 10 r = num2%10; //store the each digit in arr2 arr2[i] = r; num2 = num2 / 10; i++; //store the length of arr2 len2 = i; r=0;

// Loop to get the each digit from second number while(num2 != 0) // % - reminder of num2 / 10 r = num2%10; //store the each digit in arr2 arr2[i] = r; num2 = num2 / 10; i++; //store the length of arr2 len2 = i; r=0; cout<< "Output: "; //Displays the difference between second and first integer for(i=len2-1,j=0;i>=0;i--,j++) 43- 44 45 //Subtract the second and first integer arr3[j] = arr2[i] - arr1[i]; //This Logic is used to remove the leading zeros if(arr3[j] > 0) r = 1; if(r>0) //Print the each digit cout << arr3[j]; wap return 0;

Enter first integer: 123456789 Enter second integer: 123459999 Output: 3210