Question

5. (30 pts) Propane (CH2) and Oxygen (Os) are connected via a third chamber at 150 °C. 02 (6) CsH12 () 1.50 atm 8.00 atm 102.0L 60.0L Vaccuum After the two values are opened and the gases mix, what is the mol fraction of Oxfo2 Write out the balanced combustion reaction of CH with Oz, producing H20 and CO,. (Include states)

Answer 1

Hope

considering ideal gases, we apply the ideal gas law to calculate the number of moles for CFH12 & O2 PV=nRT for C6H12 For O₂ P-1.50 atm, V = 602 P= 8 aton, V = 102L - PV Thing n₂ = 8x10. 1.50 x 60 0.082*(273 +150) 0-082 (273+150) = 23.53 mol - 1050x60 = 2.50 mol 0.082x423 @ when two values are opened, then they will mix, then, mot fraction of O₂ (8) = 120 n = RT 23.53 23.53 +2:59 23.53 26.12 = 0.90 6 Balanced combustion equation: C3 Hg (8) + 5O2 (8) 3 CO₂ (9) + 4H₂0 (1)